Garlic Knots in Colorado Springs

3 restaurants in Colorado Springs list garlic knots on their menus. The cheapest is Borriello Brothers at $4.95. The typical price across town is $8.99, and the dearest we found is $10.49 at Papa's Italian Restaurant, so the two ends of the list are $5.54 apart, which is 112% more for the same dish. Of the 3 kitchens listed, 1 charges more than a dollar under the typical price, 1 sits within a dollar of it and 1 charges more than a dollar over.

We track garlic knots in 174 other areas and compare them all on garlic knots across United States. The typical price there runs $6.95 at the median, so Colorado Springs is dearer than most of them, with a lower typical price than 19 of the 174. The lowest best price anywhere we cover is $4.00 at Fratelli's Pizza & Pasta in Clifton, NJ, and the highest best price is $9.99 in Thousand Oaks, CA. The nearest area with it is Denver, about 61 mi away, where the best price is $5.99.

Where is the cheapest garlic knots in Colorado Springs? Borriello Brothers, at $4.95 on 215 East Platte Avenue. The same dish reaches $10.49 elsewhere in town, so where you order it changes the bill by $5.54.

What should garlic knots cost here? About $8.99 is the typical price across the 3 kitchens in Colorado Springs that list it. Of the ones listed above, 1 is more than a dollar below that and 1 is more than a dollar above, so the typical price is a middle rather than a floor.

Is it cheaper nearby? The nearest area we track it in is Denver, about 61 mi away, where the best price is $5.99. That is $1.04 more than the best price here.

Why do the prices differ so much? We compare what each menu calls the same dish, and menus are not identical: portion, cut, sides and the kind of room you are sitting in all ride on the price, and none of that shows up in a number. Part portions and half sizes are kept out of this comparison, and a chain charging the same at several addresses is counted once, so the spread above is between genuinely different kitchens rather than the same one repeated.